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Amazing

Your twerking

Thanks, I was very confused on how to use y~mx1+b, this video helped alot :)

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YOOOO THIS WAS BETTER THAN HOW MY TEACHER TAUGHT IT

The way you explained this was awesome! and the fact that you look happy doing math inspires me to also see math as a fun hobby instead of thinking it as a hard subject :D

due to how complex this method is, i think this would drive a mathematician insane so i tried it with 1101.64 and here's how it went: 1. i had to *estimate* which square is the largest without going over, most commonly done with *trial and error* (i got 33) 2. oh right you have to divide it into groups of 2 digits (__ . __ is ok, and not _ _._ _) 3. write the estimated number to the left of the √ symbol and above (the last digit of that number should be uhhhhh just write that placed down like normal long division) 4. the decimal i wanted to square root had digits after the decimal point, so copy that down (but if it has 1 or 0, then just write zeros instead) (so i have "≤ 1264" 5. uhhhhhhhhh 2:12 yeah i have no idea how to explain this part (i write 1 here) 6. ............. ………………………………………… and you just repeat step 5 and 6

Is a slide rule same as a caculator?

Is a slide rule same as a caculator?

What is a slide rule, used for?

What is a slide rule, used for?

then how about 37?

Maybe I'm a little slow, I was okay till ya added (2) 00 zeros! Why do you add the two zeros, what's the purpose?😂

W VIDEO and W TEACHER🤙🤙❤‍🔥🔥👍

1 million views and just 10k likes?? Bro thats unfair

That's Genius. Idk why haven't this got more views

Biggest stupid

So many more subs than me

So much helpful, thank you

Damn this is actually epic thanks captain

Verbose

Thank you so much

Thanks. appreciate that.

very cool we can get an exact answer. How does it work?

Such a fascinating video, i could watch these sort of lectures for hours.

The process here is really Newton's method based on finding the intersection of the tangent line at the estimated square root. You could have picked 7, or any number, and it will converge to the root. Example 38/7 = 5.43, add 7, 12.43, divide by 2, 6.21. 38/6.21 = 6.11, add 6.21 = 12.32, divide by 2 = 6.16. Reason - d/dx x^2 = 2x thus the division by 2. You can use the same method to take cube roots or nth roots depending on your patience :) You are estimating a function by its tangent line at the point in question.

Thank you, Sir! But if I may ask, what went through your mind that you thought of this method? What made you go beyond the comfortable boundary and thought "Ey, this could work!"?

This video is titled , "How to Find the length of a Cord". What the hell are you doing showing how to covert degrees into radians.. Stay the course lad.

I completely disagree. I believe you illustrated this information brilliantly. We can mince words all day long but the heart of the issue is clear. I walk away with a simple understanding that ten other videos couldn't bring into focus for me. So thank you.

I wonder how long it would take to do the whole process

Thank you for your help. I got an A on my assignment 😊👍

To be Honest for me this is a rare tutorial video on how to find the square root of non-perfect square numbers

جاکش مزخرف است

This not a short cut method |!

Wouldn't this be close enough? Especially as the number you are working with the result gets closer and closer to the exact answer? ruclips.net/video/t9Hhkk0TB1g/видео.html

Calculator to nhi chahiye pr D scale ki zrurt pdegi😅

Why in the world are you using the Protractor?!

Thank God for calculators!

👍

:O this is so easy! thanks!

lefthanded brother and sister!

Using your method find the square root of 600

My mistake, i meant to say 38 not 36.

Why don't you just divide 36 by 6 and take it to 2 decimal places?

I would rather stick to iterative comparisons

Couldn't you just divide the remainder by 2 times the numerator in the division step? Another words, in your example, divide 2 by 12.

Cool but this taught me nothing. :)

I did the next digit...and got 4.

This neat method is based on the binomial coefficients. For square root, it's derived from a^2+2ab+a^2 as such: a^2 + b(2a+b). A similar but more complex method gives cube root: a^3 + b(3a^2+3ab+b^2). For fourth root, it's a^4 + b(4a^3+6a^2b+4ab^2+b^3). Fifth root is a^5 + b(5a^4+10a^3*b+10a^2*b^2+5ab^3+b^4), and so forth. You would bring down groups of three 0s, four 0s, and five 0s, respectively. It's doable by hand for cube root, but rapidly grows to involve gigantic multiplicands when used for higher roots. Nonetheless, it works.